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11. Circles
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Q6 of 141 Page 420

In the given figure, and calculate

(i) (ii) (iii)


(i)


∠ABD and ∠ACD are in the segment AD.


∴ ∠ACD = ∠ABD [Angles in the same segment of a circle]


∠ACD = 54°


(ii) ∠BAD = 43°


∠BAD and ∠BCD are in the segment BD.


∴ ∠BAD = ∠BCD [Angles in the same segment of a circle]


∠BAD = 43°


(iii)


In triangle ABD,


∠ABD + ∠BAD + ∠BAD = 180°[Sum of angles of triangle]


⇒ 54° + 43° + ∠BAD = 180°


⇒ 97° + ∠BAD = 180°


⇒ ∠BAD = 83°


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Questions · 141
11. Circles
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