Q23 of 141 Page 447

In the given figure, O is the centre of a circle and ∠OAB = 50°. Then, ∠CDA = ?

Given: ∠OAB = 50°


Construction: Join AC


Here,


In ΔAOB


OA = OB (radius)


∠OAB = ∠OBA (angles opposite to equal sides are equal)


∴ ∠OBA = 50°


∠OBA = ∠CDA (angles in the same segment)


∴ ∠CDA = 50°

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