Q7 of 141 Page 438

In the given figure, is the center of the given circle and measure of arc is 100°. Determine and

∠ADC = (1/2) ∠AOC


⇒ ∠ADC = (1/2) 100°


⇒ ∠ADC = 50°


Now,


∠ADC + ∠ABC = 180°[ABCD is a cyclic quadrilateral]


⇒ 50° + ∠ABC = 180°


⇒ ∠ABC = 130°


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