Q37 of 141 Page 447

In the given figure, O is the centre of a circle and ∠AOB = 130°. Then, ∠ACB = ?

Given: ∠AOB = 130°


Here,


(Exterior ∠AOB) = 360° – (interior ∠AOB)


(Exterior ∠AOB) = 360° – 130°


(Exterior ∠AOB) = 230°


We know that,


(Exterior ∠AOB) = 2 × ∠ACB


230° = 2 × ∠ACB


∠ACB = = 115°


∴ ∠ACB = 115°

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