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11. Circles
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Q9 of 141 Page 438

In the adjoining figure, is a cyclic quadrilateral in which and Find

ABCD is a cyclic quadrilateral


∴ ∠BCD + ∠BAD = 180°[Opposite angle of a cyclic quadrilateral are supplementary]


⇒ 100° + ∠BAD = 180°


⇒ ∠BAD = 80°


In triangle ABD,


∠ADB + ∠ABD + ∠BAD = 180°[Sum of angles of triangle]


⇒ ∠ADB + 50° + 80° = 180°


⇒ ∠ADB + 130° = 180°


⇒ ∠ADB = 50°


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11. Circles
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