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11. Circles
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Q2 of 141 Page 438

In the given figure, is a diameter and is a cyclic quadrilateral. If find

In cyclic quadrilateral PQRS,


∠PSR + ∠PQR = 180°[Opposite angles]


⇒ 150° + ∠PQR = 180°


⇒ ∠PQR = 30°


In triangle PQR,


∠RPQ + ∠PQR + ∠PRQ = 180°[Sum of angles of triangle]


⇒ ∠RPQ + 30° + 90° = 180°


⇒ ∠RPQ + 120° = 180°


⇒ ∠RPQ = 60°


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In the given figure, is a cyclic quadrilateral in which

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Questions · 141
11. Circles
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