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Mathematics
11. Circles
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Q8 of 141 Page 438

In the given figure, is equilateral. Find (i) (ii)

(i)


ABC is equilateral triangle.


∴ ∠ABC = ∠ACB = ∠BAC = 60°____________________ (i)


∠BDC = ∠BAC = 60°[Angles in the same segment of a circle are equal]


(ii)


ABCD is a cyclic quadrilateral


∴ ∠BAC + ∠BEC = 180°


⇒ 60° + ∠BEC = 180°


⇒ ∠BEC = 120°


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Questions · 141
11. Circles
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