Q2 of 83 Page 76

Verify whether the given value of x is a solution of the quadratic equation or not:

x2 + x — 2 = 0, x = 2

x = 2 will be solution of quadratic equation x2 + x — 2 = 0 if x = 2 satisfies the given equation


put x = 2 in L.H.S of x2 + x — 2 = 0


L.H.S = 22 – 2 + 2


L.H.S = 4


L.H.S ≠ R.H.S


Thus x = 2 does not satisfies the equation x2 + x — 2 = 0 hence x = 2 is not a solution


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