Verify whether the given value of x is a solution of the quadratic equation or not:
x2 + x — 2 = 0, x = 2
x = 2 will be solution of quadratic equation x2 + x — 2 = 0 if x = 2 satisfies the given equation
put x = 2 in L.H.S of x2 + x — 2 = 0
⇒ L.H.S = 22 – 2 + 2
⇒ L.H.S = 4
⇒ L.H.S ≠ R.H.S
Thus x = 2 does not satisfies the equation x2 + x — 2 = 0 hence x = 2 is not a solution
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