Solve the following equations using the method of factorization:

27x² — 48 = 0

27 and 48 are divisible by 3 take factor 3 common

⇒ 3 × (9x² – 16) = 0

⇒ 9x² – 16 = 0

⇒ (3x)² – 4² = 0

Using the identity (a + b)(a – b) = a² – b²

Where a = 3x and b = 4

⇒ (3x + 4)(3x – 4) = 0

⇒ 3x + 4 = 0 or 3x – 4 = 0

⇒ 3x = – 4 or 3x = 4

Therefore and