Q3 of 83 Page 90

Divide 20 into two parts such that the sum of the square of the parts is 218.

Let the divided two parts be x and 20 – x.

x2 + (20 – x)2 = 218


x2 + 400 – 40x + x2 = 218


2x2 – 40x + 182 = 0


Dividing the whole equation by 2, we get –


x2 – 20x + 91 = 0


x2 – (7 + 13)x + 91 = 0


x2 – 7x – 13x + 91 = 0


x(x – 7) – 13(x – 7) = 0


(x – 7)(x – 13) = 0


x – 7 = 0 or x – 13 = 0


x = 7 or x = 13


the two parts are 7 and 13.


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