Divide 20 into two parts such that the sum of the square of the parts is 218.
Let the divided two parts be x and 20 – x.
⇒ x2 + (20 – x)2 = 218
⇒ x2 + 400 – 40x + x2 = 218
⇒ 2x2 – 40x + 182 = 0
Dividing the whole equation by 2, we get –
⇒ x2 – 20x + 91 = 0
⇒ x2 – (7 + 13)x + 91 = 0
⇒ x2 – 7x – 13x + 91 = 0
⇒ x(x – 7) – 13(x – 7) = 0
⇒ (x – 7)(x – 13) = 0
⇒ x – 7 = 0 or x – 13 = 0
⇒ x = 7 or x = 13
∴ the two parts are 7 and 13.
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