Find the discriminant of the following quadratic equations and discuss the nature of the roots:
√6 x2 — 5x + √6 = 0
√6x2 – 5x + √6 = 0
Comparing equation √6x2 – 5x + √6 = 0 with ax2 + bx + c = 0 we get
a = √6, b = – 5 and c = √6
Discriminant (D) = b2 – 4ac
⇒ D = (– 5)2 – 4(√6)(√6)
⇒ D = 25 – 4 × 6
⇒ D = 25 – 24
⇒ D = 1
As D > 0 roots of equation √6x2 – 5x + √6 = 0 are real and distinct
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