Verify whether the given value of x is a solution of the quadratic equation or not:

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x = 1 will be solution of quadratic equation ![]()
if x = 1 satisfies the given equation
put x = 1 in L.H.S of 1/(3x + 1) – 1/(2x – 1) + 3/4 = 0
⇒ L.H.S ![]()
⇒ L.H.S ![]()
⇒ L.H.S ![]()
⇒ L.H.S ![]()
⇒ L.H.S = 0
⇒ L.H.S = R.H.S
Thus x = 1 satisfies the equation
hence x = 1 is a solution
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