15x² — 16x + 1 = 0

15x² — 16x + 1 = 0

⇒ 15x² – 15x – x + 1 = 0

taking 15x common from first two terms and – 1 common from next two

⇒ 15x(x – 1) – 1(x – 1) = 0

⇒ (15x – 1)(x – 1) = 0

⇒ 15x – 1 = 0 or x – 1 = 0

⇒ 15x = 1 or x = 1

Therefore and x = 1