Q4 of 83 Page 76

6x² + 13x + 6 = 0

⇒ 6x² + 9x + 4x + 6 = 0

taking 3x common from first two terms and 2 common from next two

⇒ 3x(2x + 3) + 2(2x + 3) = 0

⇒ (3x + 2)(2x + 3) = 0

⇒ 3x + 2 = 0 or 2x + 3 = 0

⇒ 3x = – 2 or 2x = – 3

Therefore and

Solve the following equations using the method of factorization:

27x² — 48 = 0

(x — 7)² — 16 = 0

15x² — 16x + 1 = 0

Questions · 83

4. Quadratic Equations

1 1 1 1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4 4 4 1 1 1 1 1 1 2 3 3 4 5 5 5 5 5 5 1 2 3 4 5 6 7 8 1 1 1 1 1 2 2 2 2 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 23 23 23 23 23 23 23

6x2 + 13x + 6 = 0