Soma has drawn a right angled triangle ABC whose ABC = 90, AB = 24 cm. and BC = 7 cm. By calculating, let us write the value of sinA, cosA, tanA and cosec A.

Given, AB = 24, BC = 7
Need to find the values of sinA, cosA, tanA and cosecA
⇒ [from the figure, AC is hypothesis, AB is base and CB is perpendicular]
⇒ AC2 = AB2 + BC2
⇒ AC2 = (24)2 + (7)2
= 576 + 49
= 625
⇒ AC2 = 625
⇒ AC = 25
⇒ ![]()
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= 0.28
⇒ sinA = 0.28
⇒ ![]()
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= 0.96
⇒ cosA = 0.96
⇒ ![]()
= ![]()
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= 0.29
⇒ tanA = 0.29
⇒ ![]()
= ![]()
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= 3.57
⇒ cosecA = 3.57
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