Q3 of 80 Page 311

If then let us determine the value of sin θ + cos θ.

Given,


⇒ squaring on both sides


⇒


⇒


⇒


⇒


⇒


⇒ sin2θ + cos2 θ = 1, Can be written as


⇒ (sinθ + cosθ)2 – 2sinθcosθ = 1


⇒


⇒


⇒


⇒


⇒


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