If
then let us show that, x sin θ = y cos θ.
Given, ![]()
⇒ sin2θ + cos2θ = 1
⇒ sin2θ = 1-cos2θ
= ![]()
= ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ 
⇒ ![]()
⇒ ![]()
⇒ xsinθ = ycosθ
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