In a right angled triangle PQR, ∠Q=90°, ∠R=45°; if PR = 3√2, then let us find out the lengths of two sides PQ and QR.

To Find: PQ and QR
Given: PR = 3√2 and ∠Q=90°, ∠R=45°
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PQ = 3
Now, we also know that
cos θ = ![]()
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QR = 3
Hence PQ = 3 units and QR = 3 units
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