If cos θ = 0.6, then let us show that, (5 sin θ – 3 tan θ) = 0.
Given, cosθ = 0.6
⇒ ![]()
= 0.6 =
= ![]()
[we know that hypothesis2 = perpindicular2 + base2]
⇒ (5)2 = P2 + 32
⇒ 25 = P2 + 9
⇒ P = 4
⇒ ![]()
= ![]()
⇒ ![]()
= ![]()
⇒ 5sinθ – 3tanθ
= ![]()
= 4-4
= 0
Hence, proved
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