Q3 of 80 Page 311

If cosec θ + cot θ = √3, then let us determine the values of both cosec θ and cot θ.

Given, cosecθ + cotθ = √3


⇒ cosecθ + cotθ = √3 ……..eq(1)


⇒ cosec2θ –cot2θ = 1


⇒ (cosecθ + cotθ)(cosecθ –cotθ) = 1


⇒ (√3)(cosecθ –cotθ) = 1


⇒ ………eq(2)


From adding both the equations we get


⇒


⇒


⇒


⇒


⇒


⇒


⇒


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