If cot θ = 2, then let us determine the values of tan θ and sec θ and show that 1+ tan2 θ = sec2 θ.
Given, cotθ = 2
Need to show 1 + tan2θ = sec2θ
⇒
= 2
⇒
= ![]()
⇒ hypothesis2 = perpindicular2 + base2
= 1 + 22
= 5
⇒ hypothesis = √5
⇒
= ![]()
⇒ 1 + tan2θ = ![]()
= ![]()
= ![]()
⇒ sec2θ = ![]()
= ![]()
∴ LHS = RHS
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