If sin θ + sin2 θ = 1, then let us prove that, cos2 θ + cos4 θ = 1.
Given, sinθ + sin2θ = 1
⇒ sinθ + sin2θ = sin2θ + cos2θ
⇒ sinθ = cos2θ
⇒ squaring on both sides
⇒ (sinθ)2 = (cos2θ)2
⇒ sin2θ = cos4θ
⇒ sinθ + sin2θ = 1
⇒ cos2θ + cos4θ = 1
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