If in a right angled triangle ABC, ∠C=90°, DC = 21 unit and AB = 29 units, then let us find the values of sinA, cosA, sinB and cosB.
Given, BC = 21 and AB = 29
Need to find the values of sinA, cosA,sinB,cosB
⇒
and ![]()
⇒ AB2 = AC2 + BC2
⇒ (29)2 = AC2 + (21)2
⇒ 841 = AC2 + 441
⇒ 400 = AC2
⇒ AC = 20
⇒ ![]()
=
= 0.72
⇒ ![]()
=
= 0.68
⇒ ![]()
=
= 0.68
⇒ ![]()
=
= 0.72
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