Q3 of 80 Page 311

If tan θ × cot θ = 2, then let us determine the value of (tan θ - cot θ).

Given, tanθ + cotθ = 2


⇒


⇒


⇒ tan2θ -2tanθ + 1 = 0


⇒ (tanθ -1)(tanθ -1) = 0


∴ tanθ = 1


⇒ = 1


⇒ tanθ –cotθ = 0


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