If
and sec θ + cosec θ + x, then the value of x is
Given, sinθ –cosθ = 0
⇒ squaring on both sides
⇒ (sin2θ + cos2θ -2sinθ cosθ) = 0
⇒ (1-2sinθ cosθ ) = 0
⇒ ![]()
⇒ secθ + cosecθ = x
⇒ ![]()
⇒ ![]()
⇒ sinθ + cosθ = x sinθ cosθ
⇒ sinθ + cosθ = ![]()
Squaring on both sides
⇒ ![]()
⇒ ![]()
⇒ x2 = 8
⇒ x = 2√2
⇒ Option A is incorrect as it does not satisfy the value
⇒ Option B is incorrect as it does not satisfy the value
⇒ Option C is incorrect as it does not satisfy the value
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