If
cot then let us determine the values of cos A and cosec A and show that 1 + cot2 A = cosec2A.
Given, ![]()
⇒ ![]()
= ![]()
[we know that hypothesis2 = perpindicular2 + base2]
⇒ h2 = 7.52 + 42
= 72.25
⇒ h = 8.5
⇒ ![]()
= ![]()
⇒ ![]()
= ![]()
⇒ 1 + cot2A = ![]()
= ![]()
= ![]()
= 1.28
⇒ cosec2A = ![]()
= ![]()
= 1.28
∴ 1 + cot2A = cosec2A
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