Q3 of 80 Page 311

If then let us determine the values of both sec θ and tan θ.

Given,


⇒ -----eq(1)


⇒ sec2θ –tan2θ = 1


⇒ (secθ + tanθ)(secθ –tanθ) = 1


⇒ (


⇒ secθ + tanθ = √3………eq(2)


From adding both the equations we get


⇒


⇒


⇒


⇒


⇒


⇒


⇒


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