If 2x = sec A and
then the value of
is
⇒ Given, 2x = secA and ![]()
⇒ ![]()
⇒![]()
= ![]()
= ![]()
= ![]()
⇒ Option B is incorrect as it does not satisfy the value
⇒ Option C is incorrect as it does not satisfy the value
⇒ Option D is incorrect as it does not satisfy the value
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