A chemist has one solution which is 50% acid and second which is 25% acid. How much of each should be mixed to form 10 liters of 40% of acid solutions?
Let 50% acidic solution be x litre and 25% acidic solution is y litre
Combine them to form 10 litre 40% acidic solution
Number of mole should be equal in both side so,
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Multiplying by 100 from both the sides
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And other condition is volume conservation
So, total volume of solution is 10 litre
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Putting the value of x in equation (1)
50(10–y) + 25y = 400
500–50y + 25y = 400
25y = 100
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y = 4
x = 6
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