A shopkeeper buys some packets of biscuits for rupees 80. Had he bought four more packets for the same amount each packet would have cost rupees 1 less. How many packets did he buy?
Let the cost of each packet be x
And the number of packet y
So, 1st statement
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He bought more 4 packet = y + 4
Cost of each packet = x – 1
So, 2nd statement,
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By putting the value of x from equation (1)
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Multiplying by y from both the side
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y(y + 20)–16(y + 20) = 0
(y + 20)(y–16) = 0
y = 16,–20
We never consider negative value at this type of problem
Y = 16 (number of packet )
X = 5 (amount per packet)
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