The first three terms of an AP are (3y – 1), (3y + 5) and (5y + 1), the value of y is _____.
OR
If 18, a, (b – 3) are in AP, then value of (2a – b) is ____.
Let three terms are a1, a2 and a3.
Then, a2 – a1 = a3 – a2
Substituting the values, we get
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The value of y is 5.
OR
Let three terms are a1, a2 and a3.
Then, a2 – a1 = a3 – a2
Substituting the values, we get
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The required value is 15.
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