PA and PB are two tangents drawn from an external point P to a circle with centre C and radius 4 cm. If PA ⊥ PB, then length of each tangent is _______.
The diagram is given below.

It is given that, ∠APB = 90° [PA ⊥ PC]
After joining AC and BC, we find that PACB is a square.
∠CAB and ∠CBP are both 90° as radii of a circle is perpendicular to the tangent at the point of contact.
Hence, PA = PB = 4cm.
Couldn't generate an explanation.
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