If angles A
Let the angles A, B and C be ‘a – d’, ‘a’ and ‘a + d’ respectively
[In AP]
By Angle sum property of triangle, we have
∠A + ∠B + ∠C = 180°
⇒ a – d + a + a + d = 180
⇒ 3a = 180
⇒ a = 60°
⇒ ∠B = 60°
OR
Put n = 1
a1= 3(1)2 – 5 = 3 – 5 = -2
Put n = 2
a2= 3(2)2 – 5 = 12- 5 = 7
Put n = 3
a3= 3(3)2 – 5 = 27 – 5 = 22
Common difference, d1= a2 – a1 =7 – (-2) = 9
Common difference, d2 = a3 – a2 = 22 – 9 = 13
Since, d1 ≠ d2
Therefore, it’s not an A.P.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
