Q4 of 180 Page 4

If angles A

Let the angles A, B and C be ‘a – d’, ‘a’ and ‘a + d’ respectively


[In AP]


By Angle sum property of triangle, we have


A + B + C = 180°


a – d + a + a + d = 180


3a = 180


a = 60°


B = 60°


OR


Put n = 1


a1= 3(1)2 – 5 = 3 – 5 = -2


Put n = 2


a2= 3(2)2 – 5 = 12- 5 = 7


Put n = 3


a3= 3(3)2 – 5 = 27 – 5 = 22


Common difference, d1= a2 – a1 =7 – (-2) = 9


Common difference, d2 = a3 – a2 = 22 – 9 = 13


Since, d1 ≠ d2


Therefore, it’s not an A.P.


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