A square is inscr

Given: radius of the quadrant = 28cm

This will be the diagonal of the square.

Let the side of the square = acm

By Pythagoras theorem,

a² + a² = 28²

2a² = 784

a² = 392cm²

We know that, Area of square = (side)² = a²

Therefore, Area of square = 392cm²

Now, Area of a quadrant of a circle = 1/4πr²

Putting r = 28cm, we get

Area of a quadrant of a circle

Area of a quadrant of a circle = (22 × 28) cm²

Area of a quadrant of a circle = 616cm²

Area of shaded region = Area of a quadrant of the circle – Area of square

Area of shaded region = (616 – 392) cm²

Hence, the area of the shaded region is 224 cm²

OR

Given: Length of the minute hand = 10cm

First, we need to calculate the angle swept by the minute hand from 6:10 to 7:05

In 60 minutes, minute hand sweep 360˚.

Therefore, in 1 minute it will sweep

Difference in minutes from 6:10 to 7:05 = 55 minutes

The angle swept by the minute hand = 55 × 6˚

Therefore, the angle swept by minute hand = 330˚

We know that area of sector

Here, θ = 330˚ and r = 10cm

Therefore,

Area swept by minute hand

Area swept by minute hand

Area swept by minute hand = 288.1 cm²