In the given fig. DE || BC, ∠ADE =70° and ∠BAC=50°, then ∠BCA = ______

OR
In the given figure, AD = 2cm, BD = 3 cm, AE = 3.5 cm and AC = 7 cm. Is DE parallel to BC ?

By converse of Thale’s theorem DE II BC
∠ADE = ∠ABC = 70°
Given ∠BAC = 50°
∠ABC + ∠BAC + ∠BCA =180° (Angle sum property of triangles)
700 + 500 + ∠BCA = 180°
∠BCA = 180° - 120° = 60°
OR
EC = AC – AE = (7- 3.5) cm = 3.5 cm
![]()
So, ![]()
Hence, by converse of Thale’s Theorem, DE is not Parallel to BC.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.