The quadratic equation
has _______ roots.
OR
The pair of linear equations 2x + 4y = 3 and 12y + 6x = 6 has/have _______ solutions/s.
The discriminant value of a quadratic equation ax2 + bx + c = 0, a ≠ 0 is given by,
D = b2 – 4ac = 0
Given, ![]()
⸫ D = b2 – 4ac
⇒ D = (– √5)2 – 4(2)(1)
⇒ D = – 3
Here, D < 0
Hence, the roots of the quadratic equation
are imaginary.
OR
Given pair of equations are,
2x + 4y – 3 = 0 and 6x + 12y – 6 = 0
Here, a1 = 2, b1 = 4, c1 = – 3
And a2 = 6, b2 = 12, c2 = – 6
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Here, ![]()
Hence, the given pair of linear equations has no solution.
Couldn't generate an explanation.
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