One card is drawn from a well-shuffled deck of 52 cards. Find the probability of drawing

(i) an ace (ii) a red king (iii) a diamond

OR

Two different dice are thrown together. Find the probability that the numbers obtained

(i) have a sum less than 7 (ii) is a doublet of odd numbers

Total number of cards = 52

We know, Probability of an event E is

P(E)

(i) Total number of possible outcomes = 52

The favourable outcomes = No. of aces in a deck = 4

P(an ace) =

(ii) Total number of possible outcomes = 52

The favourable outcomes = No. of red kings = 2

P(a red king) =

(iii) Total number of possible outcomes = 52

The favourable outcomes = No. of diamonds = 13

P(a diamond) =

OR

When two dices are tossed together, possible outcomes are

{ (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

(i) Total number of possible outcomes = 36

Number of favourable outcomes = 15 [(1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1)]

P (have a sum less than 7) =

(ii) Total number of possible outcomes = 36

Number of favourable outcomes = 9 [(1,1), (1,3), (1,5), (3,1), (3,3), (3,5), (5,1), (5,3), (5,5)]

P (doublet of odd numbers) =