Q27 of 180 Page 4

Since the number leaves the remainder 9 and 7 when divides 285 and 1249 respectively.


number completely divides 285 – 9 = 276 and 1249 – 7 = 1242


And greatest of that number will be HCF(276, 1242)


Now, 1242 = 276 × 4 + 138


276 138 × 2 + 0


So, HCF(276, 1242) = 138 and that is required number.


OR


Composite numbers are those numbers which have a factor other than 1 and itself.


For example: 28 is a composite number as 28 = 2 × 2 × 7 and has factors other than 1 and 28.


Now,


(7 × 11 × 13 + 13)


= 13(7 × 11 + 1)


= 13 × 78


Since this number has two factors other than 1 and itself it is a composite number.


And


(7×6×5×4×3×2×1 + 5)


= 5(7 × 6 × 4 × 3 × 2 + 5)


= 5(1008 + 5)


= 5 × 1013


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