Calculate the perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is
OR
The point which divides the line segment joining the points (7, - 6) and (3, 4) in ratio 1:2 internally lies in which quadrant?
We plot the vertices of a triangle i.e., (0, 4), (0, 0) and (3, 0) on the paper shown as given below

Now, perimeter of ΔAOB = Sum of the length of all its sides:
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Distance between the points ![]()
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= Distance between A(0, 4) and O(0, 0) + Distance between O(0, 0) and B(3, 0)
+ Distance between A(0, 4) and B(3, 0)

Hence, the required perimeter of triangle is 12.
OR
Let’s take A and B the joining point and P is the dividing point;
Let’s assume the co - ordinates of point P = x and y
By using Section formula;
x co - ordinate of point P will be -
x =
and
y co - ordinate of point P will be -
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؞ x = ![]()
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Given that,
x1 = 7, y1 = - 6,
x2 = 3, y2 = 4
m = 1 and
n = 2
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So, (x, y) =
lies in IV quadrant.
[Since, in IV quadrant, x - coordinate is positive and y - coordinate is negative]
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