Q1 of 95 Page 14

Two opposite angles of a parallelogram are (3x-2)° and (50-x)°. Find the measure of each angle of the parallelogram.

Given,


Two opposite angles of a parallelogram (3x - 2) and (50 – x)


Opposite angles of a parallelogram are equal,


3x – 2 = 50 – x


4x = 52∘


X = 13∘


So, angles are


3x – 2 = 3×13-2 = 37∘


50 – x = 50 -13 = 37∘


Sum of other two angles = 360 - 2×37 = 360 – 74 = 286∘


So each angle will be = ∘


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