Q32 of 95 Page 15

In ΔABC, E is the mid-point of median AD such that BE produced meets AC at F. If AC = 10.5 cm, then AF=

Given,


In ∆ABC


E is mid point of median AD



AC = 10.5 cm


Draw DM││EF


∵ E is mid point of AD so F is mid point of AM


AF= FM ……………………(i)


In ∆BFC


EF││DM


SO, FM = MC ………………….(ii)


From(i) &(ii)


AF= MC……………..(iii)


AC = AF+MC+FM


= AC= AF+AF+AF From (i) (ii) &(iii)


AC = 3AF


AF =


AF =

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