Q3 of 95 Page 14

Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle.

Given,


Let the smallest angle = x∘


Than the other angle = (2x – 24)°


So,


x∘+x∘+2x – 24 + 2x – 24 = 360∘


6x = 360 + 48 = 408



Other angles = 2x – 24 = 2×68 – 24 = 136-24 = 112∘


Angles are = 68∘, 68∘, 112∘, 112∘


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If an angle of a parallelogram is two-third of its adjacent angle, find the angles of the parallelogram.

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The perimeter of a parallelogram is 22 cm. If the longer side measures 6.5 cm. what is the measure of the shorter side?

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In a parallelpgram ABCD, ∠D=135°, determine the measures of ∠A and ∠B.