Q31 of 95 Page 15

P is the mid point of side BC of a parallelogram ABCD such that ∠BAP =∠DAP. If AD=10 cm, then CD=

Given,


ABCD is a parallelogram,



P is mid point of side BC


∠BAP = ∠DAP


AD = 10cm


∵ AD││BC


∠DAP = ∠APB [alternate angles]


∠DAP = ∠BAP


AB = BP (side opposite to equal angles)


= BP =


∴ AB =


AB = CD = 5cm (sides of parallelogram)


Hence , CD = 5 cm

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