Q4 of 95 Page 15

In a quadrilateral ABCD, bisectors of angles A and B intersect at O such that ∠AOB=75°, then write the value of ∠C+∠D.

Given,



In quadrilateral ABCD


∠x+∠y+75° = 180° (angle sum property of triangle)


= ∠x+∠y = 180°-75° = 105°


=2(∠x+∠y) = 2×105° = 210°


∴ ∠C+∠D = 360°-210° = 150°


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