Q26 of 95 Page 15

In a rhombus ABCD, if ∠ACB =40°, then ∠ADB =

Given,


ABCD is a rhombus


∠ACB = 40°



∵ ∠DAC =∠ACB = 40° [alternate angles]


∠AOD = 90° [ diagonals of rhombus are perpendicular to each other]


In ∆AOD


∠AOD+∠ADO+∠DAO = 180°


∠ADO+90°+40° = 180°


= ∠ADO = 180°- 130° = 50°


=∠ADO=∠ADB = 50°

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