Q14 of 95 Page 15

In a parallelogram ABCD, the bisector of ∠A also bisects BC at X. Find AB : AD.


Given,


In parallelogram ABCD ,


Bisector of ∠A bisects BC at X


∵ AD││BC and AX cuts them so


∠DAX = ∠AXB (alternate angles)


∠DAX = ∠XAB (AX is bisector of ∠A)


∴∠AXB = ∠XAB


AB= BX (sides opposite of equal angles)


Now,


=


=


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