ABCD is a parallelogram and E and F are the centroids of triangles ABD and BCD respectively, then EF=
Given,
ABCD is a parallelogram
E & F are centroids of ∆ABD & ∆BCD respectively
We know that diagonals of parallelogram bisect each other & centroid of a median divides it in 2:1
So, in ∆ABD ,
= ![]()

Similarly, ![]()
= AO = CO
= ![]()
From equations (i) & (ii)
EO = FO
EF = 2 FO…………..(III)
AE = CF……(IV)
From equation (i)
= AE = ![]()
=AE = ![]()
= AE = ![]()
= AE = ![]()
=![]()
= ![]()
= ![]()
= AE= EF
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