ABC is a triangle. D is a point on AB such that AD=
AB and E is a point on AC such that AE=
AC. Prove that DE=
BC.
Given,
Let P and Q be the mid points of AB and AC respectively

Then, PQ ││BC and PQ=
…………….(i)
In ∆APQ, D and E are mid points of AP and AQ resp.
∴DE││PQ , DE=
………….(ii)
From (i) and(ii)
=DE= ![]()
= DE = ![]()
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