Q18 of 95 Page 15

ABCD is a parallelogram M is the mid-point of BD and BM bisects ∠B. Then, ∠AMB=

Given,


ABCD is a parallelogram,



M is mid point of BD


BM bisects ∠B


∵ ∠A+∠B = 180° [adjacent angles of parallelogram are supplementary]


In ∆AMB , ∠AMB+


= ∠AMB +


=∠AMB +


= ∠AMB = 180° - 90° = 90°

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