In Fig. 14.99, ABCD is a parallelogram in which P is the mid-point of DC and Q is a point on AC such that CQ=
AC. If PQ produced meets BC at R, Prove that R is a mid-point of BC.

Given,
Join B and D suppose AC and BD cut at D

Then, OC = ![]()
Now, CQ =![]()
= CQ =
= ![]()
In ∆DCO, P & Q are midpoints of DC & OC
∴ PQ![]()
Also in ∆COB , Q is mid point of OC and QR││OB
∴ R is mid point of BC
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